Question

A block of mass 1.00 K.g rests on a horizontal surfaces. A force of 0.500 K.g is required to start the block into motion. Compute the coefficient of friction.

Answer 1

Answer on Question 66655, Physics, Mechanics, Relativity

Question:

A block of mass $1.0 \, kg$ rests on a horizontal surface. A force of $0.5 \, N$ is required to start the block into motion. Compute the coefficient of static friction.

Solution:

Applying the Newton’s Second Law of Motion we get (at the moment when the block begins to move the acceleration is zero):

$$\sum F _ {x} = m a _ {x} = 0,$$ $$F _ {a p p l} - F _ {s. f r.} = 0.$$ $$F _ {a p p l} = F _ {s. f r.} = \mu_ {s} N = \mu_ {s} m g.$$

From this formula we can find the coefficient of static friction between the block and the horizontal surface:

$$\mu_ {s} = \frac {F _ {a p p l}}{m g} = \frac {0 . 5 \, N}{1 . 0 \, k g \cdot 9 . 8 \, \frac {m}{s ^ {2}}} = 0. 0 5.$$

Answer:

$$\mu_ {s} = 0. 0 5.$$

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