Question

A bullet of mass 20 g, travelling at a speed of 350 m/s, strikes a steel plate at an angle of 30 degree with the plane of plate. it ricochets off at the same angle, at a speed of 320 m/s. What is the magnitude of the impulse that the steel plate gives to the projectile ?If the collision with the plate takes place over a time delta t=10^3 s, what is the average force exerted by the plate on the bullet?

Answer 1

Answer on Question #66195, Physics / Mechanics | Relativity

A bullet of mass $20\mathrm{g}$ , travelling at a speed of $350\mathrm{m/s}$ , strikes a steel plate at an angle of 30 degree with the plane of plate. It ricochets off at the same angle, at a speed of $320\mathrm{m/s}$ . What is the magnitude of the impulse that the steel plate gives to the projectile? If the collision with the plate takes place over a time delta $t = 10^{\wedge}3$ s, what is the average force exerted by the plate on the bullet?

Find: $\Delta p - ?\Delta F - ?$

Given:

$\mathrm{m} = 20 \times 10^{-3} \mathrm{~kg}$

$\theta = 30{}^{\circ}$

$\mathrm{v} = 350 \mathrm{~m} / \mathrm{s}$

$\mathrm{u} = 320 \mathrm{~m} / \mathrm{s}$

$\Delta t = 10^{-3} \mathrm{~s}$

Solution:

Magnitude of the impulse $\Delta p$ :

$\Delta p = p_{1} + p_{2}$ (1)

Magnitude of the impulse $p_1$ :

$p_1 = \mathrm{mv}\sin \theta (2)$

Magnitude of the impulse $p_2$ :

$p_2 = \mathrm{mu}\sin \theta (3)$

(2) and (3) in (1):

$\Delta p = m \sin \theta (v + u)$ (4)

Of (4) $\Rightarrow \Delta p = 6.7\mathrm{kg}\times \mathrm{m / s}$

Average force:

$$\Delta F = \frac {\Delta p}{\Delta t} (5)$$ $$Of (5) \Rightarrow \Delta F = 6700 N$$

**Answer:**

6.7 kg×m/s

6700 N

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