Question

2. N’dea, an ACCESS student, has a mass of 87.5 kg. Her new bicycle has a mass of 14.6 kg. N’dea is pedaling so that a net (unbalanced) force of 7.87 N accelerates her and her bicycle. What is the value of the acceleration
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Answer 1

Answer on Question 65768, Physics, Mechanics, Relativity

Question:

N’dea, an ACCESS student, has a mass of $87.5 \, kg$. Her new bicycle has a mass of $14.6 \, kg$. N’dea is pedaling so that a net (unbalanced) force of $7.87 \, N$ accelerates her and her bicycle. What is the value of the acceleration?

Solution:

By the definition of the Newton’s Second Law of Motion we have:

$$F_{net} = (M + m)a,$$

here, $M$ is the mass of N’dea, $m$ is the mass of the bicycle, $F_{net}$ is the net force acting on the N’dea and her bicycle, $a$ is the acceleration.

Then, from this formula we can find the value of the acceleration:

$$a = \frac{F_{net}}{(M + m)} = \frac{7.87 \, N}{(87.5 \, kg + 14.6 \, kg)} = 0.077 \, \frac{m}{s^2}.$$

Answer:

$$a = 0.077 \, \frac{m}{s^2}.$$

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