Question #65639

The linear density of a vibrating string is 1.3 × 104 kg m1. A transverse wave is propagating on the string and is described by the equation y (x, t) = 0.021 sin (30t x) where x and y are in metres and t is in seconds. Calculate the tension in the string.
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Expert's answer

2017-03-06T11:52:05-0500

Answer on Question #65639, Physics / Mechanics | Relativity

The linear density of a vibrating string is 1.3×104kgm11.3 \times 10^{-4} \, \mathrm{kg} \, \mathrm{m}^{-1}. A transverse wave is propagating on the string and is described by the equation y(x,t)=0.021sin(30tx)y(x, t) = 0.021 \sin(30t x) where xx and yy are in metres and tt is in seconds. Calculate the tension in the string.

Solution:

v=fλ=2πω2πk=ωk=301=30m/sv = f \lambda = \frac{2 \pi \omega}{2 \pi k} = \frac{\omega}{k} = \frac{30}{1} = 30 \, \mathrm{m/s}v=Tμv = \sqrt{\frac{T}{\mu}}T=μv2T = \mu v^2T=1.3104×302=0.117NT = 1.3 \cdot 10^{-4} \times 30^2 = 0.117 \, \mathrm{N}

Answer: 0.117 N

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