Question #65500

A pendulum bob of mass 50 g is suspended on a string from the ceiling of an elevator which is moving downwards with an acceleration 1.5 ms-2. Draw the free body diagram using the non-inertial frame of reference and determine the tension in the string. (Take g = 10 ms-2)
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Expert's answer

2017-03-02T11:48:05-0500

Answer on Question #65500, Physics / Mechanics | Relativity

A pendulum bob of mass 50 g is suspended on a string from the ceiling of an elevator which is moving downwards with an acceleration 1.5 ms-2. Draw the free body diagram using the non-inertial frame of reference and determine the tension in the string. (Take g = 10 ms-2)

Find: T - ?

Given:


m=50×103 kgm = 50 \times 10^{-3} \text{ kg}a=1.5 m/s2a = 1.5 \text{ m/s}^2g=10 m/s2g = 10 \text{ m/s}^2


Solution:



Newton's Second Law:


F=ma(1)\vec{F} = m\vec{a} \quad (1)Of(1)mg+T=ma(2),\text{Of} \quad (1) \Rightarrow m\vec{g} + \vec{T} = m\vec{a} \quad (2),


where mgm\vec{g} is gravity force, T\vec{T} is tension force

Projections on axis OY: mgT=mamg - T = ma (3)


Of(3)T=m(ga)(4)\text{Of} \quad (3) \Rightarrow T = m(g - a) \quad (4)Of(4)T=0.425 N\text{Of} \quad (4) \Rightarrow T = 0.425 \text{ N}


Answer:

0.425 N

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