A solid cylinder of mass 3.0 kg and radius 1.0 m is rotating about its axis with a speed of 40 rad s-1. Calculate the torque which must be applied to bring it to rest in 10s. What would be the power required?
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Expert's answer
2017-03-01T11:47:05-0500
Mass of the cylinder, m = 3.0 kg Angular speed, ω = 40 rad s–1 Radius of the cylinder, r = 1.0 m Time t = 10 s The moment of inertia of the solid cylinder: τ = Iα I = mr2 / 2 α = ω / t τ = m ω r2 / 2 t τ = 3 kg x 40 rad s–1 x (1.0 m)2 / 2 x 10 s = 6 N m
Power given by P = ω τ P = 6 N m x 40 rad s–1 = 240 Wt
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