Question

Two metallic spheres of mass M are suspended by two strings each of length L.The distance between upper ends of strings is L.The angle which strings will make due to mutual attaction sphere is(if each mass horizontally moved by distance of L/4 mutual attraction)

Answer 1

Answer on Question #65088-Physics-Mechanics-Relativity

Two metallic spheres of mass $M$ are suspended by two strings each of length $L$ . The distance between upper ends of strings is $L$ . The angle which strings will make due to mutual attraction sphere is (if each mass horizontally moved by distance of $L/4$ mutual attraction)

Solution

From the graph we can see that

$$\tan \theta = \frac {F}{m g}$$ $$\tan \theta = \frac {4 G m}{g L ^ {2}}$$

The angle which strings will make due to mutual attraction sphere is

$$\theta = \tan^ {- 1} \frac {4 G m}{g L ^ {2}}$$

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