Question

A block weighing 7 N requires a force of 2.7 N to push it along at constant velocity.
What is the coefficient of friction for the surface?

Answer 1

Answer on Question #64571, Physics / Mechanics | Relativity

A block weighing 7 N requires a force of 2.7 N to push it along at constant velocity. What is the coefficient of friction for the surface?

Solution:

Write Newton's second law

ma = f + W + N + Ffr

ma = 0

Ox: $F_{fr} = f$

Oy: $N = W$

Friction force

$F_{fr} = \mu N$

$\mu W = f$

$\mu = f / W$

$\mu = 2.7 \mathrm{~N} / 7 \mathrm{~N} = 0.39$

Answer: 0.39

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