Question

An object is traveling with a constant acceleration of 10 meter per second square how much distance will it travel in 3rd second of its journey

Answer 1

Answer on Question 64231, Physics, Mechanics, Relativity

Question:

An object is traveling with a constant acceleration of $10\,m/s^2$. How much distance will it travel in 3-rd second of its journey?

Solution:

We can find the distance traveled by the object from the kinematic equation:

$$d = v_0 t + \frac{1}{2} a t^2,$$

here, $v_0$ is the initial velocity of the object, $a$ is the acceleration of the object, $t$ is time.

Since the object initially starts from rest ($v_0 = 0\,m/s$), we get:

$$d_3 = \frac{1}{2} a t^2 = \frac{1}{2} \cdot 10\, \frac{m}{s^2} \cdot (3\, s)^2 = 45\, m.$$ $$d_2 = \frac{1}{2} a t^2 = \frac{1}{2} \cdot 10\, \frac{m}{s^2} \cdot (2\, s)^2 = 20\, m.$$ $$\Delta d = d_3 - d_2 = 25\, m.$$

Answer:

$$\Delta d = 25\, m.$$

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