Question #6408

A piece of ice of mass 50kg is pushed with a velocity of 5m/s along a horizontal surface.as a result of friction between the piece of ice and the surface,the piece stops after travelling 25m,the ice melted in the process is_____________.

Expert's answer

A piece of ice of mass 50kg is pushed with a velocity of 5m/s along a horizontal surface. as a result of friction between the piece of ice and the surface, the piece stops after travelling 25m, the ice melted in the process is ___________.

Kinetic energy, which ice has:


W=Mv22W = \frac {M v ^ {2}}{2}


Energy which need to melt peace of ice of mass MMM_{M}:


Q=λMMQ = \lambda M _ {M}


where λ\lambda - specific heat of fusion.

All kinetic energy was used to melt ice using friction force:


Mv22=λMMMM=Mv22λ\frac {M v ^ {2}}{2} = \lambda M _ {M} \rightarrow M _ {M} = \frac {M v ^ {2}}{2 \lambda}MM=50kg(5m/s)22334103J/kg=1.87103kgM _ {M} = \frac {5 0 k g * (5 m / s) ^ {2}}{2 * 3 3 4 * 1 0 ^ {3} J / k g} = 1. 8 7 * 1 0 ^ {- 3} k g


Answer: MM=1.87103kgM_{M} = 1.87 * 10^{-3} kg

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