Question #64001

A satellite with a mass of 2273 kg is at an altitude of 42873 km above the surface of Saturn what is the strength of the gravitational force on the satellite
1

Expert's answer

2016-12-09T11:30:09-0500

Answer on Question #64001, Physics / Mechanics | Relativity

Question:

A satellite with a mass of 2273 kg is at an altitude of 42873 km above the surface of Saturn. What is the strength of the gravitational force on the satellite?

Solution:

Gravitational force between two bodies may be calculated according to this formula:


Fgr=Gm1m2R2,F _ {g r} = G \frac {m _ {1} m _ {2}}{R ^ {2}},


where GG — gravitational constant (6.674×1011m3kg1s2)(6.674 \times 10^{-11} \, \text{m}^3 \, \text{kg}^{-1} \, \text{s}^{-2}),

m1m_{1} and m2m_{2} — masses of the bodies,

RR — distance between its centres.

In our case we must take into account Saturn’s radius (58232 km) and mass (5.683·10²⁶ kg).

So R=42873+58232km=101105km1.011108mR = 42873 + 58232 \, \text{km} = 101105 \, \text{km} \cong 1.011 \cdot 10^{8} \, \text{m}

And thus Fgr=6.674×101122735.6831026(1.011108)2=8434NF_{gr} = 6.674 \times 10^{-11} \frac{2273 \cdot 5.683 \cdot 10^{26}}{(1.011 \cdot 10^{8})^{2}} = 8434 \, \text{N}

Answer:

8434 N

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