Question

the average day on Jupiter in 10 hours. If the average angular acceleration is -5 x 10(to the negative 10 power) radians per second squared, how many earth days does it take for jupiter to stop rotating?

Answer 1

Answer on Question #63811-Physics-Mechanics

The average day on Jupiter is 10 hours. If the average angular acceleration is -5 x 10(to the negative 10 power) radians per second squared, how many earth days does it take for Jupiter to stop rotating?

Solution

$$\omega = \frac {2 \pi}{T}.$$ $$\omega - \alpha t = 0$$ $$t = \frac {\omega}{\alpha} = \frac {2 \pi}{T \alpha} = \frac {2 \pi}{(1 0 \cdot 3 6 0 0) (5 \cdot 1 0 ^ {- 1 0})} = 3 4 9 0 6 6 s = \frac {3 4 9 0 6 6}{(2 4 \cdot 3 6 0 0)} d a y s = 4 d a y s.$$

Answer: 4 days.

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