Question #63262

a lady and a child pushing a shopping trolley. the lady pushes with a force of 40N and child with a force of 10N. whats horizontal force and name of forces acting on the trolley
1

Expert's answer

2016-11-11T09:43:11-0500

Answer on Question 63262, Physics, Mechanics, Relativity

Question:

A lady and a child pushing a shopping trolley. The lady pushes with a force of 40N40N and child with a force of 10N10N . What is the horizontal force and name of forces acting on the trolley.

Solution:

Here's the sketch of our problem:



There are five forces that act on the shopping trolley: horizontal force F1=40NF_{1} = 40N with which a lady pushing the shopping trolley, horizontal force F2=10NF_{2} = 10N with which the child pushing the trolley, the force of gravity mgmg directed downward, the force of reaction NN directed perpendicular to the surface and the friction force FfrF_{fr} directed opposite to the horizontal force.

Since both forces F1F_{1} and F2F_{2} are parallel and act in the same direction, the resultant horizontal force applied to the trolley will be the sum of these two forces:


Fres=F1+F2=40N+10N=50N.F _ {r e s} = F _ {1} + F _ {2} = 4 0 N + 1 0 N = 5 0 N.

Answer:

Fres=50N.F _ {r e s} = 5 0 N.


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