Question

A person reached the point directly opposite on the other bank of flowing river while swimming at the speed of 5 metre per second at the angle of 120 degree with the flow the speed of flow must be

Answer 1

Answer on Question #63144, Physics / Mechanics | Relativity

A person reached the point directly opposite on the other bank of flowing river while swimming at the speed of 5 metre per second at the angle of 120 degree with the flow the speed of flow must be

Find: $v_{\text{flow}} - ?$

Given:

$\mathsf{v}_{\text{person}} = 5 \mathsf{m} / \mathsf{s}$

$\theta = 120{}^{\circ}$

Solution:

Of Figure $\Rightarrow$ sin $30{}^{\circ} = \frac{v_{\text{flow}}}{v_{\text{person}}}$ (1)

Of (1) $\Rightarrow v_{\text{flow}} = v_{\text{person}} \times \sin 30{}^{\circ}$ (2)

Of (2) $\Rightarrow v_{\text{flow}} = 2.5 \, \text{m/s}$

Answer:

2.5 m/s

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