Question

A glider with a mass of 0.3105 kg is pulled along a track by a pulley with a 0.010kg weight at the end. Compute the acceleration of the Glider.

Answer 1

Answer on Question #62688-Physics-Mechanics-Relativity

A glider with a mass of $0.3105\mathrm{kg}$ is pulled along a track by a pulley with a $0.010\mathrm{kg}$ weight at the end. Compute the acceleration of the Glider.

Solution

The second Newton's law for glider:

$$M a = T$$

$T$ is the tension in the rope.

The second Newton's law for hanging mass:

$$m a = m g - T.$$

Adding these equations we get:

$$(m + M) a = m g$$

The acceleration of the Glider is

$$a = \frac {m}{m + M} g = \frac {0 . 0 1 0}{0 . 0 1 0 + 0 . 3 1 0 5} 9. 8 1 = 0. 3 0 6 \frac {m}{s ^ {2}}$$

Answer: $0.306\frac{m}{s^2}$

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