Question

If I drop a rock off a cliff into the water and 3.4 seconds after I drop the rock I hear the splash, how high is the cliff?
What formula do I have to use to find this solution?

Answer 1

Answer on Question #62629, Physics / Mechanics | Relativity

If I drop a rock off a cliff into the water and 3.4 seconds after I drop the rock I hear the splash, how high is the cliff? What formula do I have to use to find this solution?

Find: h-?

Given:

$v_{0y} = 0 \, \text{m/s}$

$t = 3.4 \, \text{s}$

$g = 9.8 \, \text{m/s}$

Solution:

The body accelerated by gravity uniformly along OY.

Displacement:

$$h = h _ {0} + v _ {0 _ {y}} + \frac {g _ {F} t ^ {2}}{2} (1)$$ $$\text {Of} (1) \Rightarrow h = 0 + 0 + \frac {g t ^ {2}}{2} (2)$$ $$\text {Of} (2) \Rightarrow h = \frac {g t ^ {2}}{2} (3)$$ $$\text {Of} (3) \Rightarrow h = 56.644 \, \text{m}$$

Sound travels in the air after falling of rock. The sound speed in air: $340 \, \text{m/s}$. Therefore the time of movement of sound in air is a little.

Answer:

$h = 56.644 \, \text{m}$

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