Question

a pump ejects 12000 kg of water at speed of 4 m/s in 40 seconds. find the average rate at which the pump is working.

Answer 1

Answer on Question #62110, Physics / Mechanics | Relativity

A pump ejects $12000\,\mathrm{kg}$ of water at speed of $4\,\mathrm{m/s}$ in 40 seconds, find the average rate at which the pump is working.

Solution:

$$F = \frac{mv}{t}$$ $$A = F_s$$ $$s = vt$$ $$A = \frac{mv}{t} \times vt = mv^2$$

rate of working

$$P = \frac{A}{t} = \frac{mv^2}{t}$$ $$P = \frac{12000\,\mathrm{kg} \times (4\,\mathrm{m/s})^2}{40\,\mathrm{s}} = 4800\,\mathrm{Watts} = 4.8\,\mathrm{kW}$$

average rate of working is $4.8\,\mathrm{kW}$

Answer: $4.8\,\mathrm{kW}$

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