Question

1. The figure attached is water fall which is 50 m high. Water falls in a section of the fall at the rate of 1.2×106kgs−1 . How much power is generated by the fall?

2 Calculate the volume contraction of 100 mL when subjected to a pressure of 1.5 MPa
a. 0.045 mL
b. -0.071 mL
c. 0.033 mL
d. -0.027 mL

Answer 1

Answer on Question #61869-Physics-Mechanics

1. The figure attached is water fall which is $50\mathrm{m}$ high. Water falls in a section of the fall at the rate of $1.2\times 106\mathrm{kgs - 1}$. How much power is generated by the fall?

Solution

$$P = \frac {d E}{d t}.$$ $$E = m g h.$$ $$P = \frac {d m}{d t} g h = (1.2 \cdot 10^{6})(9.8)(50) = 5.9 \cdot 10^{8} W.$$

2. The bulk modulus of water is 2.1GPa. Calculate the volume contraction of 100 mL when subjected to a pressure of 1.5 MPa

a. 0.045 mL

b. -0.071 mL

c. 0.033 mL

d. -0.027 mL

Solution

$$A v _ {*} = - P v _ {*} / B$$ $$B = - P v _ {*} / \Delta v _ {*}$$ $$B = 2.1\,GPa$$ $$P = 1.5\,MPa = 1.5 \cdot 10^{6}Pa$$ $$v _ {*} = \frac {100\,ml}{1000}$$ $$\Delta v _ {*} = - \frac {P v _ {*}}{B} = - \frac {(1.5 \cdot 10^{6})(0.1)}{2.1 \cdot 10^{9}} = (-7.1 \cdot 10^{-5} mL) (1000) = -0.071\,ml$$

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