Question

Your 19.0 kg curling stone travels at 3.0 m/s[N] towards an opponents stone at rest.The stones strike and your stone rolls off to the side with a velocity of 1.8 m/s[N22W]. The opponents stone moves in a northeasterly direction. What is the final velocity of the opponents stone (With magnitude and direction - solved using vector components)

Answer 1

Your $19.0\mathrm{kg}$ curling stone travels at $3.0\mathrm{m / s[N]}$ towards an opponents stone at rest. The stones strike and your stone rolls off to the side with a velocity of $1.8\mathrm{m / s[N22W]}$ . The opponents stone moves in a northeasterly direction. What is the final velocity of the opponents stone

By the low of saving energies:

$$\frac {1 9 + 3 ^ {2}}{2} = \frac {1 9 + 1 . 8 ^ {2}}{2} + \frac {\mathrm {m} + \mathrm {v} ^ {2}}{2}$$

Where m-mass of opponents stone, v -speed

By low of saving impulses:

$$1 9 * 3 = 1. 8 * 1 9 + m v$$

From here $m = 22.8 / v$

$$\frac {1 9 + 3 ^ {2}}{2} = \frac {1 9 + 1 . 8 ^ {2}}{2} + \frac {2 2 . 8 / v + v ^ {2}}{2}$$

V=19(9-1.8*1.8)/22.8=4.8 m/s