Question

A force of 50g and a force of 60g act an angle of 37° between them. Determine the resultant using cosine law

Answer 1

Question #61257, Physics / Mechanics

A force of 50g and a force of 60g act an angle of 37° between them.

Determine the resultant using cosine law

Solution

According to the law of the cosine:

$$F^2 = F_1^2 + F_2^2 - 2 \cdot F_1 \cdot F_2 \cdot \cos\alpha;$$ $$\begin{array}{l} F = \sqrt{F_1^2 + F_2^2 - 2 \cdot F_1 \cdot F_2 \cdot \cos\alpha} \\ = \sqrt{0.25 N^2 + 0.36 N^2 - 2 \cdot 0.5 N \cdot 0.6 N \cdot 0.799} = 0.361 N; \end{array}$$

Answer the question: F=0.361 N or the resultant force 36.1 g.

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