Question

There is a tower of height H a boy throws a ball from the tower in upward direction and it reaches the ground in time T1, another boy throws a ball from the tower in direction parallel to the ground. It reaches the ground in time T2 Another boy just leaves the ball from the top of the tower and it takes time T to reach the ground. Find T with respect to T1 and T2. Please it is urgent.

Answer 1

Answer on question 61223 - Physics - Mechanics | Relativity

There is a tower of height $H$ a boy throws a ball from the tower in upward direction and it reaches the ground in time $T1$ , another boy throws a ball from the tower in direction parallel to the ground. It reaches the ground in time $T2$ . Another boy just leaves the ball from the top of the tower and it takes time $T$ to reach the ground. Find $T$ with respect to $T1$ and $T2$ .

Solution

Let's answer on this question using the figure above. It is shown all 3 cases. When a boy throws a ball in upward direction (it takes time $T_{1}$ , see fig.A), time $T_{1} > T$ , because the ball moves additional way in compare to case B. In the case C, when a ball was thrown in horizontal direction, there is no additional force in ground direction (besides the gravity force), hence time $T_{2} = T$ . Using the law of conservation energy for case B we can write: $\frac{1}{2} = mgH \rightarrow v = \sqrt{2gH} = \frac{H}{T} \rightarrow T = \sqrt{\frac{H}{2g}}$ .

Answer $T_{1} > T = T_{2}, T = \sqrt{\frac{H}{2g}}.$

http://www.AssignmentExpert.com