Question #60988

A Reciprocating Internal Combustion Engine (RICE) uses fuel of energy content 48.3 MJ/kg, at a rate of 6 kg/h. It is tested that the engine has the thermal efficiency of 25 %. Thus, determine: i) the power output in kilowatts
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Expert's answer

2016-07-28T10:14:02-0400

Answer on Question #60988-Physics-Mechanics-Relativity

A Reciprocating Internal Combustion Engine (RICE) uses fuel of energy content 48.3 MJ/kg, at a rate of 6 kg/h. It is tested that the engine has the thermal efficiency of 25%. Thus, determine: i) the power output in kilowatts

Solution

dEindm=48.3MJkg\frac {d E _ {i n}}{d m} = 4 8. 3 \frac {M J}{k g}dmdt=6kgh\frac {d m}{d t} = 6 \frac {k g}{h}η=PoutPin=0.25\eta = \frac {P _ {o u t}}{P _ {i n}} = 0. 2 5


The power output is


Pout=ηPin=ηdEindt=ηdEindmdmdt=0.2548.3103kJkg6kg3600s=20.125kW.P _ {o u t} = \eta P _ {i n} = \eta \frac {d E _ {i n}}{d t} = \eta \frac {d E _ {i n}}{d m} \frac {d m}{d t} = 0. 2 5 \cdot 4 8. 3 \cdot 1 0 ^ {3} \frac {\mathrm {k J}}{\mathrm {k g}} \cdot \frac {6 k g}{3 6 0 0 s} = 2 0. 1 2 5 k W.


Answer: 20.125 kW.

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