Question #6081

a model rocket rises with constant acceleration to a height of 3.3m, at which this point its speed is 28.0 m/s . How much time does it take to reach this height?

Expert's answer

A model rocket rises with constant acceleration to a height of 3.3m3.3\mathrm{m}, at which this point its speed is 28.0 m/s. How much time does it take to reach this height?

Assuming that initial speed is 0 we can write an equation for body, which moving with constant acceleration:


h=at22h = \frac{a t^{2}}{2}


We know rocket speed at this height, so we can wind acceleration:


a=vta = \frac{v}{t}h=vt22t=vt2t=2hvh = \frac{v t^{2}}{2 t} = \frac{v t}{2} \rightarrow t = \frac{2 h}{v}t=23.3m28m/s0.24st = \frac{2 * 3.3 \, \mathrm{m}}{28 \, \mathrm{m/s}} \cong 0.24 \, \mathrm{s}


Answer: t0.24st \cong 0.24 \, \mathrm{s}

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