Question #60703

Toss a ball upward with an initial speed of 10 m/s. Neglecting air resistance, the time it takes to reach its release point is about
(a) 4 s (b) 1 s (c) 3 s (d) 2 s
1

Expert's answer

2016-07-04T09:54:02-0400

Question #60703, Physics – Mechanics | Relativity

Toss a ball upward with an initial speed of 10m/s10 \, \text{m/s}. Neglecting air resistance, the time it takes to reach its release point is about.

(a) 4s4 \, \text{s} (b) 1s1 \, \text{s} (c) 3s3 \, \text{s} (d) 2s2 \, \text{s}


The equation of uniformly accelerated motion of the body thrown up:


0=v0gt0 = v _ {0} - g t


Where tt – the time ascent to the max height


v0=gtv _ {0} = g tt=v0gt = \frac {v _ {0}}{g}t=10m/s9,8m/s21st = \frac {10 \, \text{m/s}}{9,8 \, \text{m/s}^2} \approx 1 \, \text{s}


Since the acceleration is constant, the time during which the body rises equal to the time of its descent.

Scilicet T=2s\mathbf{T} = 2\mathbf{s}

Answer the questions:

The time it takes to reach its release point is about (d) 2 s.

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