Answer on question 60562
mass particles of 1 kg each are placed along x axis at x=1, 4, 8,...till infinity then gravitation force on a particle of mass 3kg placed on origin is?
F=Gr122m1m2→F=6.67∗10−11∗1∗3∗n=0∑∞22n1=6.67∗10−11∗3∗34=26.68∗10−11 newton
Answer F=26.68∗10−11 newton
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Diar Shrey Kumar Dubey, the sum in the equation is the geometric progression with the common ratio r=1/4 and scale factor a=1. Then sum = a/(1-r) = 4/3
Sir how to solve the summation what is the formula cause i am from a non mathematical background. kindly give an alternate method or simplify this one