Question #60562

mass particles of 1 kg each are placed along x axis at x=1, 4, 8,......till infinity then gravitation force on a particle of mass 3kg placed on origin is?
1

Expert's answer

2016-06-28T10:29:02-0400

Answer on question 60562

mass particles of 1 kg each are placed along x axis at x=1, 4, 8,...till infinity then gravitation force on a particle of mass 3kg placed on origin is?


F=Gm1m2r122F=6.67101113n=0122n=6.671011343=26.681011 newtonF = G \frac{m_1 m_2}{r_{12}^2} \rightarrow F = 6.67 * 10^{-11} * 1 * 3 * \sum_{n=0}^{\infty} \frac{1}{2^{2n}} = 6.67 * 10^{-11} * 3 * \frac{4}{3} = 26.68 * 10^{-11} \text{ newton}


Answer F=26.681011 newtonF = 26.68 * 10^{-11} \text{ newton}

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Comments

Assignment Expert
01.07.16, 16:55

Diar Shrey Kumar Dubey, the sum in the equation is the geometric progression with the common ratio r=1/4 and scale factor a=1. Then sum = a/(1-r) = 4/3

Shrey Kumar Dubey
30.06.16, 23:10

Sir how to solve the summation what is the formula cause i am from a non mathematical background. kindly give an alternate method or simplify this one

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