Question #60205

A person aiming to reach exactly opposite point on the bank of a stream is swimming with a speed of 0.5 m/s at an angle of 120 degree with the direction of the flow of the water. The speed of water in the stream is
(1)0.25 m/s
(2)0.5 m/s
(3)1.0 m/s
(4)0.433 m/s
1

Expert's answer

2016-05-31T10:37:02-0400

Answer on Question #60205-Physics-Mechanics-Relativity

A person aiming to reach exactly opposite point on the bank of a stream is swimming with a speed of 0.5 m/s at an angle of 120 degree with the direction of the flow of the water. The speed of water in the stream is

(1) 0.25 m/s0.25 \mathrm{~m} / \mathrm{s}

(2) 0.5 m/s0.5 \mathrm{~m} / \mathrm{s}

(3) 1.0 m/s1.0 \mathrm{~m} / \mathrm{s}

(4) 0.433 m/s0.433 \mathrm{~m} / \mathrm{s}

Solution


Here, VrV_{r} is the velocity of the river w.r.t. ground, VmV_{m} is the velocity of the man w.r.t. river, VV the velocity of the man w.r.t. ground.


tan90=Vmsin120Vr+Vmcos120\tan 9 0 = \frac {V _ {m} \sin 1 2 0}{V _ {r} + V _ {m} \cos 1 2 0}Vr=Vmcos120=(0.5)(0.5)=0.25msV _ {r} = - V _ {m} \cos 1 2 0 = - (0. 5) (- 0. 5) = 0. 2 5 \frac {m}{s}


Answer: (1) 0.25m/s0.25 \, \text{m/s} .

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