Question

In a collision, two trolleys stick together. What is their velocity after the collision?

BEFORE COLLISION: CART 1( 1500kg moving forward at 2m/s) CART 2( 2000kg moving backwards at -3m/s)

AFTER COLLISION: 1500kg+2000kg together.

What is their velocity after the collision?

Answer 1

Answer on Question #60167-Physics-Mechanics-Relativity

In a collision, two trolleys stick together. What is their velocity after the collision?

BEFORE COLLISION: CART 1(1500kg moving forward at 2m/s) CART 2(2000kg moving backwards at -3m/s)

AFTER COLLISION: 1500kg+2000kg together.

What is their velocity after the collision?

Solution

According to the conservation of momentum:

$$m _ {1} v _ {1} + m _ {2} v _ {2} = (m _ {1} + m _ {2}) V$$ $$V = \frac {m _ {1} v _ {1} + m _ {2} v _ {2}}{(m _ {1} + m _ {2})} = \frac {(1 5 0 0 (2) + 2 0 0 0 (- 3))}{(1 5 0 0 + 2 0 0 0)} = - 0. 8 6 \frac {m}{s}.$$

Answer: $0.86\frac{m}{s}$ backwards.

https://www.AssignmentExpert.com