Question #60022

A model rocket fired from the ground
ascends with constant upward acceleration.
After 1.0 s from firing a small bolt is
dropped from the rocket and after 5.0 s from
firing, its fuel is then finished. The bolt
strikes the ground after 2.0 s from the instant
it was dropped. Acceleration due to gravity
is g = 10 m/s2
.
(a) acceleration of the rocket while running
on its fuel is 8.0 m/s2
.
(b) rocket was at height 100 m above the
ground when its fuel was finished.
(c) maximum speed of the rocket during its
flight is 40 m/s
(d) total airtime of the rocket is 15 s
THE QUESTION IS HOW MANY STATEMENTS ARE TRUE?
CAN U PLEASE EXPLAIN IN DETAIL
1

Expert's answer

2016-05-20T08:58:03-0400

Answer on Question #60022, Physics – Mechanics | Relativity

A model rocket fired from the ground ascends with constant upward acceleration.

After 1.0 s from firing a small bolt is dropped from the rocket and after 5.0 s from firing, its fuel is then finished. The bolt strikes the ground after 2.0 s from the instant it was dropped. Acceleration due to gravity is g=10m/s2g = 10 \, \text{m/s}^2.

(a) acceleration of the rocket while running on its fuel is 8.0m/s28.0 \, \text{m/s}^2

(b) rocket was at height 100 m above the ground when its fuel was finished.

(c) maximum speed of the rocket during its flight is 40m/s40 \, \text{m/s}

(d) total airtime of the rocket is 15 s

THE QUESTION IS HOW MANY STATEMENTS ARE TRUE?

CAN U PLEASE EXPLAIN IN DETAIL

Solution:

Equations for rocket:


h1=at122a=v1t1\begin{array}{l} h_1 = \frac{a t_1^2}{2} \\ a = \frac{v_1}{t_1} \end{array}


where initial velocity v0=0v_0 = 0, t1=1.0t_1 = 1.0 s and aa is acceleration.

Substituting we have


h1=v1t12h_1 = \frac{v_1 t_1}{2}


Equations for bolt:


h=h1+v1t2gt222h = h_1 + v_1 t_2 - \frac{g t_2^2}{2}


where initial velocity v1v_1, t2=2.0t_2 = 2.0 s and final h=0h = 0.

We obtain system of equations:


{h1=v12h1+2v120=0\left\{ \begin{array}{c} h_1 = \frac{v_1}{2} \\ h_1 + 2 v_1 - 20 = 0 \end{array} \right.v12=202v1v1=8ms\begin{array}{l} \frac{v_1}{2} = 20 - 2 v_1 \\ v_1 = 8 \frac{\text{m}}{\text{s}} \end{array}


Thus,


a=v1t1=81=8m/s2a = \frac{v_1}{t_1} = \frac{8}{1} = 8 \, \text{m/s}^2


(a) acceleration of the rocket while running on its fuel is 8.0m/s28.0 \, \text{m/s}^2 is TRUE


h5=at522=8522=100mh_5 = \frac{a t_5^2}{2} = 8 \cdot \frac{5^2}{2} = 100 \, \text{m}


(b) rocket was at height 100m100 \, \text{m} above the ground when its fuel was finished is TRUE.

The maximum speed


v=at5=85=40 m/sv = a t _ {5} = 8 \cdot 5 = 40 \mathrm{~m/s}


(c) maximum speed of the rocket during its flight is 40m/s40\mathrm{m/s} is TRUE.

The airtime of the rocket after the fuel was finished


h=h5+v5tgt22h = h _ {5} + v _ {5} t - \frac {g t ^ {2}}{2}h5=100 mh _ {5} = 100 \mathrm{~m}v5=40msv _ {5} = 40 \frac {\mathrm{m}}{\mathrm{s}}h=0h = 05t240t100=05 t ^ {2} - 40 t - 100 = 0t=10 st = 10 \mathrm{~s}


Thus, the total time is


total time=t5+t=5+10=15 s\text{total time} = t _ {5} + t = 5 + 10 = 15 \mathrm{~s}


(d) total airtime of the rocket is 15 s is TRUE.

Output: a, b, c, d are TRUE.

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Comments

Assignment Expert
23.05.16, 19:10

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MOKSHITH
21.05.16, 06:10

amazing answer searching for this answer from so many days thank u assignment expert

JAHNAVI
20.05.16, 06:13

VERY GOOD QUESTION

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