Question

A simple pendulum made 50 oscillations in 22.3s.find its period

Answer 1

Answer on Question # 59263 – Physics – Mechanics | Relativity

A simple pendulum made 50 oscillations in 22.3 s. Find its period.

Solution:

The period of a pendulum can be found as follows:

$$T = \frac {t}{n} = \frac {22.3}{50} = 0.446 \left[ s \right],$$

where $t$ is the given period of time,

$n$ is the number of oscillations during this time.

Answer: $T = 0.446 \left[ s \right]$.

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