Question #59239

the exhaust gas of a rocket is expelled at the rate of 1300kg/s, at the velocity of 50000m/s. find the thrust on the rocket in newtron
1

Expert's answer

2016-04-15T10:38:05-0400

Answer on Question 59239, Physics, Mechanics, Relativity

Question:

The exhaust gas of a rocket is expelled at the rate of 1300kg/s1300 \, kg/s, at the velocity of 50000m/s50000 \, m/s. Find the thrust on the rocket in newton.

a) 6.5107N6.5 \cdot 10^{7} N

b) 3.5107N3.5 \cdot 10^{7} N

c) 7.6107N7.6 \cdot 10^{7} N

d) 5.7107N5.7 \cdot 10^{7} N

Solution:

We can find the thrust on the rocket from the definition of the impulse:


FtΔt=mΔv,F_{t} \Delta t = m \Delta v,


here, FtF_{t} is the force of the thrust on the rocket, Δt\Delta t is the amount of time in which the force is acting, mm is the mass of the expelled gas, Δv\Delta v is the rate of change of exhaust gas velocity.

Let's look at our equation. We can see, that in 1s1 \, s, 1.3103kg1.3 \cdot 10^{3} \, kg of the exhaust gas leaves the rocket at the velocity of 5104m/s5 \cdot 10^{4} \, m/s:


Ft1s=1.3103kg5104ms.F_{t} \cdot 1 \, s = 1.3 \cdot 10^{3} \, kg \cdot 5 \cdot 10^{4} \, \frac{m}{s}.


Then, we can calculate the force of the thrust on the rocket:


Ft=1.3103kg5104ms1s=6.5107N.F_{t} = \frac{1.3 \cdot 10^{3} \, kg \cdot 5 \cdot 10^{4} \, \frac{m}{s}}{1 \, s} = 6.5 \cdot 10^{7} \, N.


Answer:

a) 6.5107N6.5 \cdot 10^{7} N

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