Question

A driver does a round trip to ibadan from lagos,returning to his take-off point in five hours. The distance of ibadan from lagos is 130km.What is his average velocity?

Answer 1

Answer on Question 59232, Physics, Mechanics, Relativity

Question:

A driver does a round trip to Ibadan from Lagos, returning to his take-off point in five hours. The distance of Ibadan from Lagos is 130 km. What is his average velocity?

a) 52 km/h

b) 26 km/h

c) 0 km/h

d) 104 km/h

Solution:

The average velocity of an object is defined as the displacement per unit time:

$$v = \frac{\text{displacement}}{\text{time taken}}.$$

Because the driver returns to his take-off point, the displacement is equal to zero and we get:

$$v = \frac{\text{displacement}}{\text{time taken}} = \frac{0\ \text{km}}{5\ \text{h}} = 0\ \frac{\text{km}}{\text{h}}.$$

Answer:

c) 0 km/h

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