Question

a 1250 kg car increases its speed from 15.0m/s to 20.0m/s . how much work was done on the car?

Answer 1

Answer on Question # 59161 – Physics – Mechanics | Relativity

A 1250 kg car increases its speed from 15.0m/s to 20.0m/s. How much work was done on the car?

Solution:

Work done on the car can be calculated as the change of the kinetic energy of the car:

$$A = K _ {2} - K _ {1} = \frac {m v _ {2} ^ {2}}{2} - \frac {m v _ {1} ^ {2}}{2} = \frac {m (v _ {2} ^ {2} - v _ {1} ^ {2})}{2} = \frac {1 2 5 0 \times (2 0 ^ {2} - 1 5 ^ {2})}{2} = 1 0 9 3 7 5 [ \mathrm {J} ].$$

Answer: $A = 109375\ [\mathrm{J}]$.

https://www.AssignmentExpert.com