Question

A candle of diameter d is floating on a liquid in a cylindrical container of diameter D (D>>d). If it is burning at the rate of 2cm/hr then what will be the resultant ht of the candle?

Answer 1

Answer on Question #58804-Physics-Mechanics | Relativity

A candle of diameter $d$ is floating on a liquid in a cylindrical container of diameter $D$ ($D>>d$). If it is burning at the rate of $2 \, \text{cm/hr}$ then what will be the resultant rate of change of the top of the candle?

Solution

The density of candle is a half of density of liquid. Therefore, it will always remain half in liquid. Hence, if it burns $2 \, \text{cm/hr}$, the candle will come up by 1 cm from the water in 1 hour.

Answer: 1 cm/hr.

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