Question #58623

The Velocity of a 621 kg auto is changed from 10.0 m/s to 44.0 m/s in 70.7 s by external, constant force. What is the result in chambers in momentum of the car? What is the magnitude of the force?
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Expert's answer

2016-03-23T10:59:03-0400

Answer on question #58623, Physics / Mechanics — Relativity

Question The Velocity of a 621 kg auto is changed from 10.0 m/s to 44.0 m/s in 70.7 s by external, constant force. What is the result in chambers in momentum of the car? What is the magnitude of the force?

Solution Change of momentum is

Δp=mΔv=621(4410)=21114kgm/s\Delta p=m\Delta v=621\cdot(44-10)=21114\,kg\cdot m/s

Magnitude of force can be found as

F=Δpt=2111470.7298.6NF=\frac{\Delta p}{t}=\frac{21114}{70.7}\approx 298.6\,N

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