Question #58026

A player hits a football which is initially at rest and moves 22 m/s.
Find the:

a. momentum of the football if it has a mass of 0.48 kg
b. force exerted on it when the time of contact is 0.03s
c. impulse in the football
1

Expert's answer

2016-02-24T00:01:01-0500

Answer on Question 58026, Physics, Mechanics, Relativity

Question:

A player hits a football which is initially at rest and moves 22ms122 \, ms^{-1}.

Find the:

a) momentum of the football if it has a mass of 0.48kg0.48 \, kg

b) force exerted on it when the time of contact is 0.03s0.03 \, s

c) impulse in the football

Solution:

a) By definition of the momentum, we have:


p=mv=0.48kg22ms1=10.56kgms1.p = m v = 0.48 \, kg \cdot 22 \, ms^{-1} = 10.56 \, kg \, ms^{-1}.


b) Because the force is the rate of change of momentum, we get:


FΔt=Δp,F \Delta t = \Delta p,F=ΔpΔt=m(vv0)Δt=0.48kg(22ms10ms1)0.03s=352N.F = \frac{\Delta p}{\Delta t} = \frac{m(v - v_0)}{\Delta t} = \frac{0.48 \, kg \cdot (22 \, ms^{-1} - 0 \, ms^{-1})}{0.03 \, s} = 352 \, N.


c) By definition of the impulse, we have:


J=Δp=pp0=mvmv0=m(vv0)=0.48kg(22ms10ms1)==10.56kgms1.\begin{array}{l} J = \Delta p = p - p_0 = m v - m v_0 = m(v - v_0) = 0.48 \, kg \cdot (22 \, ms^{-1} - 0 \, ms^{-1}) = \\ = 10.56 \, kg \, ms^{-1}. \end{array}


Answer:

a) p=10.56kgms1p = 10.56 \, kg \, ms^{-1}.

b) F=352NF = 352 \, N.

c) J=10.56kgms1J = 10.56 \, kg \, ms^{-1}.

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