Answer on Question 58026, Physics, Mechanics, Relativity
Question:
A player hits a football which is initially at rest and moves 22ms−1.
Find the:
a) momentum of the football if it has a mass of 0.48kg
b) force exerted on it when the time of contact is 0.03s
c) impulse in the football
Solution:
a) By definition of the momentum, we have:
p=mv=0.48kg⋅22ms−1=10.56kgms−1.
b) Because the force is the rate of change of momentum, we get:
FΔt=Δp,F=ΔtΔp=Δtm(v−v0)=0.03s0.48kg⋅(22ms−1−0ms−1)=352N.
c) By definition of the impulse, we have:
J=Δp=p−p0=mv−mv0=m(v−v0)=0.48kg⋅(22ms−1−0ms−1)==10.56kgms−1.
Answer:
a) p=10.56kgms−1.
b) F=352N.
c) J=10.56kgms−1.
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