Question

At a bullet fired with a initial velocity of 900 ms at a target located 150 ft from rifle. How much time is required for the bullet to reach the target?

Answer 1

Answer on Question 58007, Physics, Mechanics, Relativity

Question:

A bullet is fired horizontally with an initial velocity of $900 \, ms^{-1}$ at a target located $150 \, ft$ from the rifle. How much time is required for the bullet to reach the target?

Solution:

In the condition of the question, the horizontal distance to the target $x$ is given in feet. Let's first convert feet to meters:

$$x = (150 \, ft) \cdot \left(\frac{12 \, in}{1 \, ft}\right) \cdot \left(\frac{2.54 \, cm}{1 \, in}\right) \cdot \left(\frac{1 \, m}{100 \, cm}\right) = 45.72 \, m.$$

Then, we can write the equation of horizontal motion of the bullet:

$$x = v_0 t,$$

here $x$ is the horizontal distance to the target, $v_0$ is the initial velocity of the bullet, $t$ is the time of flight.

From this formula we can find how much time is required for the bullet to reach the target:

$$t = \frac{x}{v_0} = \frac{45.72 \, m}{900 \, ms^{-1}} = 0.05 \, s.$$

Answer:

$$t = 0.05 \, s.$$

https://www.AssignmentExpert.com