Question

A bug completes one lap along the edge of
a circular planter of radius 23.6 cm in 17.59 s.
How fast was it traveling?

Answer 1

Answer on Question 57763, Physics – Mechanics | Relativity

Question:

A bug completes one lap along the edge of a circular planter of radius $23.6 \, \text{cm}$ in 17.59 s. How fast was it travelling?

Solution:

We can find the velocity of the bug from the formula:

$$v = \frac{s}{t},$$

here, $s$ is the distance travelling by the bug, $t$ is time.

Let's find the distance travelling by the bug (basically, it is a circumference of the circle):

$$s = 2\pi r = 2 \cdot 3.14 \cdot 0.236 \, m = 1.48 \, m.$$

Then, we can substitute $s$ into the first formula and find the velocity of the bug:

$$v = \frac{s}{t} = \frac{1.48 \, m}{17.59 \, s} = 0.084 \, \frac{m}{s}.$$

Answer:

$$v = 0.084 \, \frac{m}{s}.$$

https://www.AssignmentExpert.com