Answer on Question 57177, Physics, Mechanics, Relativity
Question:
Car A has a mass of 1000kg moving at a velocity of 20m/s collides with car B of mass 1200kg moving at 10m/s in the same direction. If the car B is shunted forward at 15m/s by the impact, what is the velocity, vAf, of the car A immediately after the crash?
Solution:
Let’s assume that both cars move in the same positive direction x. Then, we can apply the law of conservation of momentum:
mAvAi+mBvBi=mAvAf+mBvBf,
here, mA, mB is the mass of the cars, vAi, vBi is its velocities before collision and vAf, vBf is its velocities after collision.
From this equation we can find the velocity of the car A immediately after the crash:
vAf=mAmAvAi+mBvBi−mBvBf=1000kg1000kg⋅20sm+1200kg⋅(10sm−15sm)=14sm.
Answer:
vAf=14sm.
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