Answer on Question #56961-Physics-Mechanics-Relativity
A circular disk of mass 0.3 kg and radius 31 cm, initially not rotating, slips down a thin spindle onto a turntable (disk) of mass 1.9 kg and the same radius, rotating freely at 4.5 rad/s.
a) Find the new angular velocity of the combination;
b) The change in the kinetic energy?
c) If the motor is switched on after the disk has landed, what is the constant torque needed to regain the original speed in 3.3 s?
Solution
Iturntable=21⋅1.9⋅0.312=0.091295kgm2Idisc=21⋅0.3⋅0.312=0.014415kgm2ITotal=0.10571kgm2
Original angular momentum is
(L)=0.091295⋅4.5=0.4108275skgm2.
Conservation of angular momentum says this must be the same as the final angular momentum as there is no external torques on the system.
0.4108275=0.10571⋅w
Final angular speed
w=3.9srad.
b) The change in the kinetic energy is
ΔK=21(Ifwf2−Iiwi2)=21(0.10571⋅3.92−0.091295⋅4.52)=−0.12J.
c)
T=Iα=0.10571⋅3.34.5−3.9=0.019Nm.
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