Question

Ques no.12 on
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Answer 1

Answer on Question #56599-Physics-Mechanics-Relativity

5-12 A diver makes 2.5 complete revolutions on the way from a $10\mathrm{m}$ high platform to the water below. Assuming zero initial vertical velocity, calculate the average angular velocity during a dive.

Ans. [11 rad/s]

Solution

$$\omega_{avg} = \frac{\theta}{t}.$$ $$h = \frac{g t^{2}}{2} \rightarrow t = \sqrt{\frac{2h}{g}}$$ \omega_{avg} = \frac{\theta}{\sqrt{\frac{2h}{g}}} = \frac{\frac{2.5 \frac{rev}{1}}{2\pi} \cdot rad}{\sqrt{\frac{2 \cdot 10 \, m}{9.8 \, \frac{m}{s^{2}}}} = 11 \, \frac{rad}{s}.

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