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Expert's answer
2016-03-09T09:04:05-0500
Answer on Question #56595, Physics Mechanics Relativity
The flywheel of a large motor in a factory has mass 30kg and moment of inertia 67.5kg⋅m2 about rotation axis. The motor develops a constant torque of 600Nt⋅m, and the flywheel starts from rest.
(a) What is the angular acceleration of the flywheel?
(b) What is its angular velocity after making 4 revolutions?
(c) How much work is done by the motor during the first 4 revolutions?
(d) What is the average power output of the motor during the first 4 revolutions?
Solution
(a)
M=Jε
where M=600N⋅m is a constant torque; ε is the angular acceleration of the flywheel; J=67.5kg⋅m2 is moment of inertia about rotation axis.
Then
ε=M/J=600N⋅m/67.5kg⋅m2≈8.89rad/s2
(b)
Angular velocity:
ω=ω0+εtω0=0 (flywheel starts from rest).
The angle of rotation
φ=φ0+ω0t+21εt2
where ω0=0 and φ0=0 (flywheel starts from rest).
4 revolutions φ=4⋅2π, then from (3)
t=16π/ε=4π/ε=2.38s
Angular velocity after making 4 revolutions:
ω=εt=ε4π/ε=4πε=4π⋅8.89≈21.14rad/s
(c)
The work is done by the motor during the first 4 revolutions:
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