Question

QUESTION NUMBER 35 on
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Answer 1

Answer on Question #56550-Physics-Mechanics-Relativity

5-35 The angular velocity of the engine (and hence of the wheel) of a scooter is proportional to the petrol input per second. The scooter is moving on a frictionless road with uniform velocity. If the petrol input is increased by $10\%$ the linear velocity of the scooter is increased by :

(A) $50\%$

(B) $10\%$

(C) $20\%$

(D) $0\%$

- the angular momentum :

Solution

The angular velocity is

$$\omega \sim \frac {d m _ {p e t r o l}}{d t}.$$

The linear velocity is

$$v = \omega R,$$

where $R = \text{const}$ is a radius of the wheel.

Thus,

$$v = \omega R \sim \frac {d m _ {p e t r o l}}{d t}$$

So, linear velocity also is increased by $10\%$ .

Answer: (B) $10\%$ .

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