Question #56533

A block of mass m is released on a smooth inclined plane of inclination theta with the horizontal the force exerted by the plane on the bolck has a magnitude
1

Expert's answer

2016-01-19T08:28:40-0500

Answer on Question #56533-Physics-Mechanics-Relativity

A block of mass mm is released on a smooth inclined plane of inclination theta with the horizontal the force exerted by the plane on the block has a magnitude

Solution


where NN is Normal force that is perpendicular to the plane, W=mgW = mg , where mm is mass, gg is acceleration due to the gravity, and θ\theta is Angle of inclination of the plane, ff is friction force.

Plane is smooth, so f=0f = 0 .

The force exerted by the plane on the block is Normal force:

N=mgcosθN = mg\cos \theta

Answer: mgcosθmg\cos \theta

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