Question

a cricket ball of mass 500g is moving with a velocity of 10m/s hits a wall and returns with same speed in opposite direction. If the collision lasts for 0.1 sec, then find the force acting on the ball

Answer 1

Question #55315

M=500 g; V=10 m/s; dt=0,1 sec

F - ?

We write Newton's second law to strike the wall:

$M^{*}dV/dt = F$, where $dV = V - (-V)$ is absolute change of speed during the strike, $dt$ – time of collision.

Then $F=2M^{*}V/dt=2^{*}0,5^{*}10/0,1=100$ N

Answer: $F = 100$ N.

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