Question

An object is thrown upward at an angle of 37 degrees with a velocity of 10m/s from the top of a 20m high building. Where, from the foot of the building, would it land?

Answer 1

Answer on question #55223, Physics / Mechanics

Question An object is thrown upward at an angle of 37 degrees with a velocity of 10m/s from the top of a 20m high building. Where, from the foot of the building, would it land?

Solution Let us first find time of flight. Equation for vertical axis:

$h_{0}+t_{f}v_{v}-gt_{f}^{2}/2=0$

$h_{0}+v_{0}\sin 37{}^{\circ}t_{f}-gt_{f}^{2}/2=0$

$20+6t_{f}-4.9t_{t}^{2}=0$

$t\approx 2.72\,m/s$

From this we can find horizontal distance:

$s=v_{h}t_{f}=v_{0}\cos 37{}^{\circ}t_{f}=10\cdot 0.8\cdot 2.72\approx 21.7\,m$

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