Question

Given that the mass and radius of Jupiter are respectively 1.90 x 1027kg and 7.15 x 104 km, calculate the escape velocity from the surface of the planet.

Answer 1

Answer on Question55218 - Physics / Mechanics — Kinematics — Dynamics - for completion

October 1, 2015

Given that the mass and radius of Jupiter are respectively $1.90\cdot 10^{27}kg$ and $M=7.15\cdot 10^{4}km$, calculate the escape velocity from the surface of the planet.

Solution

Escape velocity can be calculated as:

$v=\sqrt{\frac{2GM}{R}}=\frac{26.7\cdot 10^{-11}\cdot 10^{27}}{7.15\cdot 10^{7}}\frac{m}{s}\approx 59.7\frac{km}{s}$