Question

The elevators in the John Hancock building in Chicago move 783 ft in 33 s.
What is their speed? Answer in units of m/s

Answer 1

Answer on Question #54745, Physics / Other

The elevators in the John Hancock building in Chicago move 783 ft in 33 s.

What is their speed? Answer in units of m/s

Solution:

Speed is mathematically given as:

$$v = \frac {d}{t}$$

Where

v is the Speed in m/s,

d is the Distance traveled in m,

t is the time taken in s.

The length of the international foot is to be exactly 0.3048 meters.

Thus,

$$v = \frac {(7 8 3 f t) \cdot 0 . 3 0 4 8}{(3 3 s)} = 7. 2 3 2 m / s \approx 7. 2 m / s$$

Answer: $7.2 \, m/s$