Question #54630

A speedboat is towing a paraglider at a constant speed and height
on the end of a light rope of length 30m, which makes an angle q
with the horizontal. The forces acting on the paraglider are the
vertical lift, L, the horizontal drag, D, his weight, W and the
tension in the rope, T.

How to draw a vector diagram to show the object is in equilibrium?
1

Expert's answer

2015-09-12T00:00:46-0400

Answer on Question# 54630- Physics / Mechanics- Kinematics

Question:

A speedboat is towing a paraglider at a constant speed and height on the end of a light rope of length 30m30\mathrm{m} , which makes an angle q\mathbf{q} with the horizontal. The forces acting on the paraglider are the vertical lift, L, the horizontal drag, D, his weight, W and the tension in the rope, T. How to draw a vector diagram to show the object is in equilibrium?

Answer:

By the Newton's second law of motion


ma=F,m \vec {a} = \vec {F},


where F\vec{F} is the net force (i.e. is the vector sum of all the forces). According to the statement of the problem we have v=const\vec{v} = \overrightarrow{const} and h=consth = const (fig. 1). It means that a paraglider is in equilibrium. Hence, a=0\vec{a} = 0 and the net force is also equals to zero. Namely,


F=L+W+T+D=0.\vec {F} = \vec {L} + \vec {W} + \vec {T} + \vec {D} = 0.


Fig. 1

The projections on the coordinate axes give


{Oy:0=LWTsin(q);Ox:0=Tcos(q)D.\left\{ \begin{array}{c} O y: 0 = L - W - T \sin (q); \\ O x: 0 = T \cos (q) - D. \end{array} \right. \Rightarrow{L=W+Tsin(q);D=Tcos(q).\left\{ \begin{array}{c} L = W + T \sin (q); \\ D = T \cos (q). \end{array} \right.


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