Question

If an airplane travels a path length of 2260 m while traveling a horizontal distance of 1070 m, what is its angle of climb?

Answer 1

Answer on Question#54365 – Physics – Mechanics | Kinematics | Dynamics

61.74°

Question

If an airplane travels a path length of $2260m$ while traveling a horizontal distance of $1070m$ , what is its angle of climb?

Solution

From trigonometry we have relation $\cos (\theta) = \frac{1070(\mathrm{cathetus})}{2260(\mathrm{hypotenuse})} = \frac{107}{226}$

Therefore, we can deduce angle: $\theta = \mathrm{acos}\left(\frac{107}{226}\right) \approx 61.74{}^{\circ}$

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