Question #54194

An object travels with velocity v = 4.0 meters/second and it makes an angle of 60.0° with the positive direction of the y-axis. Calculate the possible values of vx.
1

Expert's answer

2015-08-25T04:07:30-0400

Answer on Question #54194-Physics-Mechanics-Kinematics-Dynamics

An object travels with velocity v=4.0v = 4.0 meters/second and it makes an angle of 60.060.0{}^{\circ} with the positive direction of the x-axis. Calculate the possible values of vxv_{x} .

A. -3.5 meters/second and +3.5 meters/second

B. -2.0 meters/second and +2.0 meters/second

C. -2.5 meters/second and +2.5 meters/second

D. -3.0 meters/second and +3.0 meters/second



Solution

The magnitude of vxv_{x} is


vx=vcos60.0=4.0m e t e r ss e c o n d12=2.0m e t e r ss e c o n d.v _ {x} = v \cos 6 0. 0 {}^ {\circ} = 4. 0 \frac {\text {m e t e r s}}{\text {s e c o n d}} \cdot \frac {1}{2} = 2. 0 \frac {\text {m e t e r s}}{\text {s e c o n d}}.


Thus, the possible values of vxv_{x} are ±2.0meterssecond\pm 2.0 \frac{\text{meters}}{\text{second}} .

Answer: B. -2.0 meters/second and +2.0 meters/second.


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